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Seven white balls and three black balls are randomly placed in a row. The probability that no two black balls are placed adjacently equals1/27/152/151/3

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You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard XMathematicsProbabilityQuestionA1/2B2/15C1/3D7/15Open in AppSolutionVerified by TopprThe number of ways of placing 3 black balls at 10 places is 10C3. The number of ways in which two black balls are not together is equal to the number of ways of choosing 3 places marked withX out of eight places.XWXWXWXWXWXWXWXThis can be done in 8C3 ways. Thus, probability of the required event is=8C310C3=8×7×610×9×8=715.Was this answer helpful?22Similar QuestionsQ1Seven white balls and three black balls are randomly placed in a row. The probability that no two black balls are placed adjacently, equals?View SolutionQ27 white balls and 3 black balls are placed in a row at random. The probability that no two black balls are adjacent isView SolutionQ3A bag contains 2 white balls and 4 black balls. Another bag contains 3 white and 2 black balls. A bag and a ball are picked randomly. The probability that the ball will be white is: V...

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