Alex de Minaur

ACAPULCO, México (AP) — Alex De Minaur beat Casper Rudd 6-4, 6-4 on Saturday to become the first player to win back-to back titles in the Mexican Open since 2012.

The third-seeded De Minaur won his eighth ATP title to become the fourth player to repeat as champion in Mexico, the first since David Ferrer in 2010-12.

The 25-year-old Australian won his 10th consecutive match in Acapulco to break a four-match losing streaks in ATP finals, including Rotterdam earlier this year.

The sixth-seeded Ruud missed the chance to win his 11th title in the ATP and his first ATP 500 title.

De Minaur took an early break to take a 3-1 lead in the first set and both hold their serve for the 6-4 score in the first one.

In the second, both players exchanged breaks in the first four games and the Australian got a break in the seventh game to take the lead.